Integrand size = 26, antiderivative size = 86 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=-\frac {\frac {1}{b}+\frac {b}{a^2}}{2 d (b+a \cot (c+d x))^2}+\frac {\frac {1}{a^2}-\frac {1}{b^2}}{d (b+a \cot (c+d x))}+\frac {\log (b+a \cot (c+d x))}{b^3 d}+\frac {\log (\tan (c+d x))}{b^3 d} \]
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Time = 0.11 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3167, 908} \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {\frac {1}{a^2}-\frac {1}{b^2}}{d (a \cot (c+d x)+b)}-\frac {\frac {b}{a^2}+\frac {1}{b}}{2 d (a \cot (c+d x)+b)^2}+\frac {\log (a \cot (c+d x)+b)}{b^3 d}+\frac {\log (\tan (c+d x))}{b^3 d} \]
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Rule 908
Rule 3167
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {1+x^2}{x (b+a x)^3} \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\text {Subst}\left (\int \left (\frac {1}{b^3 x}+\frac {-a^2-b^2}{a b (b+a x)^3}+\frac {-a^2+b^2}{a b^2 (b+a x)^2}-\frac {a}{b^3 (b+a x)}\right ) \, dx,x,\cot (c+d x)\right )}{d} \\ & = -\frac {\frac {1}{b}+\frac {b}{a^2}}{2 d (b+a \cot (c+d x))^2}+\frac {\frac {1}{a^2}-\frac {1}{b^2}}{d (b+a \cot (c+d x))}+\frac {\log (b+a \cot (c+d x))}{b^3 d}+\frac {\log (\tan (c+d x))}{b^3 d} \\ \end{align*}
Time = 0.60 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.66 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {\log (a+b \tan (c+d x))-\frac {a^2+b^2}{2 (a+b \tan (c+d x))^2}+\frac {2 a}{a+b \tan (c+d x)}}{b^3 d} \]
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Time = 1.04 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.73
method | result | size |
derivativedivides | \(\frac {\frac {\ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3}}-\frac {a^{2}+b^{2}}{2 b^{3} \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {2 a}{b^{3} \left (a +b \tan \left (d x +c \right )\right )}}{d}\) | \(63\) |
default | \(\frac {\frac {\ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3}}-\frac {a^{2}+b^{2}}{2 b^{3} \left (a +b \tan \left (d x +c \right )\right )^{2}}+\frac {2 a}{b^{3} \left (a +b \tan \left (d x +c \right )\right )}}{d}\) | \(63\) |
risch | \(\frac {-2 a^{2} {\mathrm e}^{2 i \left (d x +c \right )}+2 b^{2} {\mathrm e}^{2 i \left (d x +c \right )}+4 i a b \,{\mathrm e}^{2 i \left (d x +c \right )}-2 a^{2}-2 i b a}{b^{2} \left (i a +b \right ) \left (b \,{\mathrm e}^{2 i \left (d x +c \right )}+i a \,{\mathrm e}^{2 i \left (d x +c \right )}-b +i a \right )^{2} d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right )}{b^{3} d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{b^{3} d}\) | \(160\) |
norman | \(\frac {-\frac {2 \left (a^{2}-b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{b^{2} d a}+\frac {2 \left (a^{2}-b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{b^{2} d a}-\frac {2 \left (3 a^{2}-b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a^{2} b d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )^{2}}+\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )}{b^{3} d}-\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{b^{3} d}-\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{b^{3} d}\) | \(205\) |
parallelrisch | \(\frac {\left (\left (2 a^{2}-2 b^{2}\right ) \cos \left (2 d x +2 c \right )+4 a b \sin \left (2 d x +2 c \right )+2 a^{2}+2 b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2} a -2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a \right )+\left (\left (-2 a^{2}+2 b^{2}\right ) \cos \left (2 d x +2 c \right )-4 a b \sin \left (2 d x +2 c \right )-2 a^{2}-2 b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+\left (\left (-2 a^{2}+2 b^{2}\right ) \cos \left (2 d x +2 c \right )-4 a b \sin \left (2 d x +2 c \right )-2 a^{2}-2 b^{2}\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+\left (a^{2}+b^{2}\right ) \cos \left (2 d x +2 c \right )+a^{2}-3 b^{2}}{2 \left (\left (a^{2}-b^{2}\right ) \cos \left (2 d x +2 c \right )+2 a b \sin \left (2 d x +2 c \right )+a^{2}+b^{2}\right ) b^{3} d}\) | \(268\) |
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Leaf count of result is larger than twice the leaf count of optimal. 284 vs. \(2 (84) = 168\).
Time = 0.28 (sec) , antiderivative size = 284, normalized size of antiderivative = 3.30 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {4 \, a^{2} b^{2} \cos \left (d x + c\right )^{2} - 3 \, a^{2} b^{2} - b^{4} - 2 \, {\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} b^{2} + b^{4} + {\left (a^{4} - b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (a^{3} b + a b^{3}\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right )\right )} \log \left (2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}\right ) - {\left (a^{2} b^{2} + b^{4} + {\left (a^{4} - b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \, {\left (a^{3} b + a b^{3}\right )} \cos \left (d x + c\right ) \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2}\right )}{2 \, {\left ({\left (a^{4} b^{3} - b^{7}\right )} d \cos \left (d x + c\right )^{2} + 2 \, {\left (a^{3} b^{4} + a b^{6}\right )} d \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} b^{5} + b^{7}\right )} d\right )}} \]
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\[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\int \frac {\sec {\left (c + d x \right )}}{\left (a \cos {\left (c + d x \right )} + b \sin {\left (c + d x \right )}\right )^{3}}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 315 vs. \(2 (84) = 168\).
Time = 0.24 (sec) , antiderivative size = 315, normalized size of antiderivative = 3.66 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=-\frac {\frac {2 \, {\left (\frac {{\left (a^{3} - a b^{2}\right )} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {{\left (3 \, a^{2} b - b^{3}\right )} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} - \frac {{\left (a^{3} - a b^{2}\right )} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )}}{a^{4} b^{2} + \frac {4 \, a^{3} b^{3} \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {4 \, a^{3} b^{3} \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {a^{4} b^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {2 \, {\left (a^{4} b^{2} - 2 \, a^{2} b^{4}\right )} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}} - \frac {\log \left (-a - \frac {2 \, b \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{b^{3}} + \frac {\log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{b^{3}} + \frac {\log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{b^{3}}}{d} \]
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Time = 0.35 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.72 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {\frac {2 \, \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{b^{3}} - \frac {3 \, b \tan \left (d x + c\right )^{2} + 2 \, a \tan \left (d x + c\right ) + b}{{\left (b \tan \left (d x + c\right ) + a\right )}^{2} b^{2}}}{2 \, d} \]
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Time = 26.11 (sec) , antiderivative size = 396, normalized size of antiderivative = 4.60 \[ \int \frac {\sec (c+d x)}{(a \cos (c+d x)+b \sin (c+d x))^3} \, dx=\frac {2\,\mathrm {atanh}\left (\frac {16\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{16\,a+\frac {32\,a^3}{b^2}-16\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-\frac {32\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{b^2}+\frac {32\,a^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{b}}-\frac {16\,a}{16\,a+\frac {32\,a^3}{b^2}-16\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2-\frac {32\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{b^2}+\frac {32\,a^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{b}}+\frac {32\,a^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{16\,a\,b+\frac {32\,a^3}{b}+32\,a^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-\frac {32\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{b}-16\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}\right )}{b^3\,d}-\frac {\frac {2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (3\,a^2-b^2\right )}{a^2\,b}-\frac {2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (a^2-b^2\right )}{a\,b^2}+\frac {2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (a^2-b^2\right )}{a\,b^2}}{d\,\left (a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (2\,a^2-4\,b^2\right )+a^2-4\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+4\,a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )} \]
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